12v^2-58v+56=0

Solution for 12v^2-58v+56=0 equation:

12v^2-58v+56=0

a = 12; b = -58; c = +56;
Δ = b2-4ac
Δ = -582-4·12·56
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-26}{2*12}=\frac{32}{24}
=1+1/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+26}{2*12}=\frac{84}{24}
=3+1/2
$